What is the integral from 2 to 4 of (x+y)/(55) ?

The integral from 2 to 4 of (x+y)/(55) is 1/55 (2x+6)

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integral from 2 to 4 of (x+y)/(55)

\int_{2}^{4} \frac{x + y}{55} d y

\frac{1}{55} (2 x + 6)

Solution steps

\int_{2}^{4} \frac{x + y}{55} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{55} \cdot \int_{2}^{4} x + y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{55} (\int_{2}^{4} x d y + \int_{2}^{4} y d y)

\int_{2}^{4} x d y = 2 x

\int_{2}^{4} y d y = 6

= \frac{1}{55} (2 x + 6)

\int \frac{x ( x - 8 )}{( x - 4 ) ^{3}} d x

2 (2 x^{2} + y^{2}) d x - x y d y = 0

f (x) = \frac{x - 5}{x + 3}

f (x) = 5 x^{2} - 2 x + 4

x \to - 4 + lim (\frac{- 1}{x ^{2} - 16})

What is the integral from 2 to 4 of (x+y)/(55) ?
The integral from 2 to 4 of (x+y)/(55) is 1/55 (2x+6)