What is inverse oflaplace 2/(s-2) ?

The answer to inverse oflaplace 2/(s-2) is 2e^{2t}

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inverse oflaplace 2/(s-2)

inverse laplace

\frac{2}{s - 2}

2 e^{2 t}

Solution steps

L^{- 1} {\frac{2}{s - 2}}

= L^{- 1} {2 \cdot \frac{1}{s - 2}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 2 L^{- 1} {\frac{1}{s - 2}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - 2}} = e^{2 t}

= 2 e^{2 t}

\int \frac{- x ^{2} + 2 x - 8}{( x ^{2} + 4 ) ( x - 2 )} d x

\int x^{2} 4 x + 7 d x

\int (x^{2} + 10 x) cos (x) d x

\frac{d}{d x} (arcsinh (x^{2}))

y = \frac{( e ^{x} )}{x}

What is inverse oflaplace 2/(s-2) ?
The answer to inverse oflaplace 2/(s-2) is 2e^{2t}