What is the sum from n=0 to infinity of 1/(6n+5) ?

The sum from n=0 to infinity of 1/(6n+5) is diverges

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sum from n=0 to infinity of 1/(6n+5)

n = 0 \sum \infty \frac{1}{6 n + 5}

diverges

Solution steps

n = 0 \sum \infty \frac{1}{6 n + 5}

Apply Series Limit Comparison Test:

diverges

= diverges

\frac{d}{d x} (2 e^{- 4 x^{2} + 3 x + 7})

f (x) = \frac{7}{t}

\frac{d}{d x} (ln (\frac{4 x}{x + 9}))

\int_{0}^{2} 1 + 9 x d x

\int_{6}^{9} \frac{1}{9 + ( x - 6 ) ^{2}} d x

What is the sum from n=0 to infinity of 1/(6n+5) ?
The sum from n=0 to infinity of 1/(6n+5) is diverges