What is the integral of 2/(x^2+1) ?

The integral of 2/(x^2+1) is 2arctan(x)+C

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integral of 2/(x^2+1)

\int \frac{2}{x ^{2} + 1} d x

2 arctan (x) + C

Solution steps

\int \frac{2}{x ^{2} + 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= 2 arctan (x)

Add a constant to the solution

= 2 arctan (x) + C

f (x) = \frac{x + 5}{x + 2}

\int \frac{1}{x \cdot x ^{2} - 1} d x

\frac{\partial}{\partial x} (y^{4})

\frac{d}{d x} (\frac{4 x}{x + 3})

\frac{d y}{d x} = \frac{x}{x ^{2} + 4}