What is the solution for y^'-(6y)/x =(y/(x^2))^4 ?

The solution for y^'-(6y)/x =(y/(x^2))^4 is y=(\sqrt[3]{11}x^6)/(\sqrt[3]{-3x^{11)+c_{1}}}

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y^'-(6y)/x =(y/(x^2))^4

y^{^{'}} - \frac{6 y}{x} = (\frac{y}{x ^{2}})^{4}

Solution steps

y^{'} (x) - \frac{6 y}{x} = (\frac{y}{x ^{2}})^{4}

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What is the solution for y^'-(6y)/x =(y/(x^2))^4 ?
The solution for y^'-(6y)/x =(y/(x^2))^4 is y=(\sqrt[3]{11}x^6)/(\sqrt[3]{-3x^{11)+c_{1}}}