What is the derivative of f(x)=x^3-3x+5 ?

The derivative of f(x)=x^3-3x+5 is 3x^2-3

What is the first derivative of f(x)=x^3-3x+5 ?

The first derivative of f(x)=x^3-3x+5 is 3x^2-3

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derivative of

f (x) = x^{3} - 3 x + 5

3 x^{2} - 3

Solution steps

\frac{d}{d x} (x^{3} - 3 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (5)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (5) = 0

= 3 x^{2} - 3 + 0

Simplify

= 3 x^{2} - 3

f (x) = \frac{cos ( x ) + 4}{1 - sin ( x )}

\int \frac{1}{C ^{2}} d C

\frac{d x}{d t} = \frac{( e ^{t} - e ^{- t} )}{3 + x}

y^{^{'}} + \frac{1}{x} y = 10 x^{2}

What is the derivative of f(x)=x^3-3x+5 ?
The derivative of f(x)=x^3-3x+5 is 3x^2-3
What is the first derivative of f(x)=x^3-3x+5 ?
The first derivative of f(x)=x^3-3x+5 is 3x^2-3