What is the sum from n=0 to infinity of (3/7)^{n/2} ?

The sum from n=0 to infinity of (3/7)^{n/2} is converges

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sum from n=0 to infinity of (3/7)^{n/2}

n = 0 \sum \infty (\frac{3}{7})^{\frac{n}{2}}

converges

Solution steps

n = 0 \sum \infty (\frac{3}{7})^{\frac{n}{2}}

Apply Series Ratio Test:

converges

= converges

\int_{- 1}^{1} \frac{1}{2} x^{3} - 2 x + 2 d x

\int \frac{1}{x ^{3}} sin (\frac{1}{x}) d x

y^{^{''}} - 2 y^{^{'}} - 3 y = 24 t e^{2 t}, y (0) = 5, y^{^{'}} (0) = 0

\frac{d}{d x} (x (4))

What is the sum from n=0 to infinity of (3/7)^{n/2} ?
The sum from n=0 to infinity of (3/7)^{n/2} is converges