What is the tangent of y=(4x)/(x+1),(3,3) ?

The tangent of y=(4x)/(x+1),(3,3) is y= 1/4 x+9/4

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tangent of y=(4x)/(x+1),(3,3)

tangent of

y = \frac{4 x}{x + 1}, (3, 3)

y = \frac{1}{4} x + \frac{9}{4}

Solution steps

Find the slope of

y = \frac{4 x}{x + 1} : \frac{d y}{d x} = \frac{4}{( x + 1 ) ^{2}}

Compute the slope of

y = \frac{4 x}{x + 1}

(3, 3) : m = \frac{1}{4}

Find the line with slope m=

\frac{1}{4}

and passing through

(3, 3) : y = \frac{1}{4} x + \frac{9}{4}

y = \frac{1}{4} x + \frac{9}{4}

6 x^{2} + 4 x - 3

\int \frac{x ^{n + 1}}{n + 1} d x

\frac{d}{d x} (ln^{x} (x))

\frac{d}{d t} (\frac{1}{e ^{t}})

f (x) = \frac{1 + 3 x}{1 - 3 x}

What is the tangent of y=(4x)/(x+1),(3,3) ?
The tangent of y=(4x)/(x+1),(3,3) is y= 1/4 x+9/4