What is the solution for (dy)/(dx)+2xy= x/(y^2),y(0)=0 ?

The solution for (dy)/(dx)+2xy= x/(y^2),y(0)=0 is y=\sqrt[3]{(-e^{-3x^2}+1)/2}

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(dy)/(dx)+2xy= x/(y^2),y(0)=0

\frac{d y}{d x} + 2 x y = \frac{x}{y ^{2}}, y (0) = 0

Solution steps

\frac{d y}{d x} + 2 x y = \frac{x}{y ^{2}}

Solve separable ODE:

\int 21 x^{20} d x

f (x) = \frac{2 x + 4 x ^{2}}{( 1 + 4 x ) ^{2}}

\int \frac{13}{x ^{3} - 125} d x

2 y = 4 x, 2 y + x = 5, y = 5

x \to 4 lim (3 x^{3} - 5 x^{2} + x - 5)

What is the solution for (dy)/(dx)+2xy= x/(y^2),y(0)=0 ?
The solution for (dy)/(dx)+2xy= x/(y^2),y(0)=0 is y=\sqrt[3]{(-e^{-3x^2}+1)/2}