What is the derivative of F(t)=e^{8tsin(2t)} ?

The derivative of F(t)=e^{8tsin(2t)} is e^{8tsin(2t)}*8(sin(2t)+2tcos(2t))

What is the first derivative of F(t)=e^{8tsin(2t)} ?

The first derivative of F(t)=e^{8tsin(2t)} is e^{8tsin(2t)}*8(sin(2t)+2tcos(2t))

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derivative of

F (t) = e^{8 t s i n (2 t)}

e^{8 t s i n (2 t)} \cdot 8 (sin (2 t) + 2 t cos (2 t))

Solution steps

\frac{d}{d t} (e^{8 t s i n (2 t)})

Apply the chain rule:

e^{8 t s i n (2 t)} \frac{d}{d t} (8 t sin (2 t))

= e^{8 t s i n (2 t)} \frac{d}{d t} (8 t sin (2 t))

\frac{d}{d t} (8 t sin (2 t)) = 8 (sin (2 t) + 2 t cos (2 t))

= e^{8 t s i n (2 t)} \cdot 8 (sin (2 t) + 2 t cos (2 t))

f (x) = sin (3 x + 1)

\int 39 sec^{- 2} (x t a) n^{3} x d x

x \to 0 lim (sin (x + x^{3}))

\frac{e ^{x^{2} - 1}}{2 x}

\frac{d y}{d x} = e^{4 x + y}

What is the derivative of F(t)=e^{8tsin(2t)} ?
The derivative of F(t)=e^{8tsin(2t)} is e^{8tsin(2t)}*8(sin(2t)+2tcos(2t))
What is the first derivative of F(t)=e^{8tsin(2t)} ?
The first derivative of F(t)=e^{8tsin(2t)} is e^{8tsin(2t)}*8(sin(2t)+2tcos(2t))