What is the derivative of-(sin(x)/(cos(x))) ?

The derivative of-(sin(x)/(cos(x))) is -sec^2(x)

What is the first derivative of-(sin(x)/(cos(x))) ?

The first derivative of-(sin(x)/(cos(x))) is -sec^2(x)

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\frac{d}{d x} (- \frac{sin ( x )}{cos ( x )})

- sec^{2} (x)

Solution steps

\frac{d}{d x} (- \frac{sin ( x )}{cos ( x )})

Simplify

- \frac{sin ( x )}{cos ( x )} : - tan (x)

= \frac{d}{d x} (- tan (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (tan (x))

Apply the common derivative:

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= - sec^{2} (x)

y = x^{3} - 2 x + 2, (2, 6)

\frac{d}{d x} (2 \cdot e^{x})

\int cot^{\frac{- 5}{4}} (2 x) csc^{4} (2 x) d x

\frac{\partial}{\partial x} (y e^{x} - 3)

a^{9} + cos^{9} (x)

What is the derivative of-(sin(x)/(cos(x))) ?
The derivative of-(sin(x)/(cos(x))) is -sec^2(x)
What is the first derivative of-(sin(x)/(cos(x))) ?
The first derivative of-(sin(x)/(cos(x))) is -sec^2(x)