What is the derivative of 6cos(3x+3) ?

The derivative of 6cos(3x+3) is -18sin(3x+3)

What is the first derivative of 6cos(3x+3) ?

The first derivative of 6cos(3x+3) is -18sin(3x+3)

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derivative of

6 cos (3 x + 3)

- 18 sin (3 x + 3)

Solution steps

\frac{d}{d x} (6 cos (3 x + 3))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (cos (3 x + 3))

Apply the chain rule:

- sin (3 x + 3) \frac{d}{d x} (3 x + 3)

= - sin (3 x + 3) \frac{d}{d x} (3 x + 3)

\frac{d}{d x} (3 x + 3) = 3

= 6 (- sin (3 x + 3) \cdot 3)

Simplify

= - 18 sin (3 x + 3)

y = e^{7 x}

y^{2} + 4 y + 20

\frac{\partial}{\partial y} (sin (\frac{2 x}{y}))

e^{2 t} cos (2 t)

\int sin^{5} (x) cos^{2} (x) d x

What is the derivative of 6cos(3x+3) ?
The derivative of 6cos(3x+3) is -18sin(3x+3)
What is the first derivative of 6cos(3x+3) ?
The first derivative of 6cos(3x+3) is -18sin(3x+3)