What is the limit as x approaches-1 of e^{1/(x+1)} ?

The limit as x approaches-1 of e^{1/(x+1)} is diverges

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limit as x approaches-1 of e^{1/(x+1)}

x \to - 1 lim (e^{\frac{1}{x + 1}})

diverges

Solution steps

x \to - 1 lim (e^{\frac{1}{x + 1}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (e^{\frac{1}{x + 1}}) = \infty

x \to - 1 - lim (e^{\frac{1}{x + 1}}) = 0

= diverges

y^{^{''}} - 5 y^{^{'}} = (5 t + 9) sin (2 t)

4 x - 2

\frac{d}{d x} ((2 x + 1) (3 x^{2} + 6))

\int (x^{3} + 10 x - 3) d x

\frac{8}{s ( s + 8 )}

What is the limit as x approaches-1 of e^{1/(x+1)} ?
The limit as x approaches-1 of e^{1/(x+1)} is diverges