What is the derivative of-18x-(17/x) ?

The derivative of-18x-(17/x) is -18+(17)/(x^2)

What is the first derivative of-18x-(17/x) ?

The first derivative of-18x-(17/x) is -18+(17)/(x^2)

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\frac{d}{d x} (- 18 x - \frac{17}{x})

- 18 + \frac{17}{x ^{2}}

Solution steps

\frac{d}{d x} (- 18 x - \frac{17}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (18 x) - \frac{d}{d x} (\frac{17}{x})

\frac{d}{d x} (18 x) = 18

\frac{d}{d x} (\frac{17}{x}) = - \frac{17}{x ^{2}}

= - 18 - (- \frac{17}{x ^{2}})

Simplify

= - 18 + \frac{17}{x ^{2}}

\frac{y ^{3}}{9} + \frac{3}{4 y}

\frac{1 - 2 x ^{3}}{x ^{4} + 3 x ^{2} - 6}

\int (- 8 y^{3}) d y

\int t^{3} e^{- 5 t} d t

What is the derivative of-18x-(17/x) ?
The derivative of-18x-(17/x) is -18+(17)/(x^2)
What is the first derivative of-18x-(17/x) ?
The first derivative of-18x-(17/x) is -18+(17)/(x^2)