What is (\partial)/(\partial x)(x^2-6xy+y) ?

The answer to (\partial)/(\partial x)(x^2-6xy+y) is 2x-6y

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(\partial)/(\partial x)(x^2-6xy+y)

\frac{\partial}{\partial x} (x^{2} - 6 x y + y)

2 x - 6 y

Solution steps

\frac{\partial}{\partial x} (x^{2} - 6 x y + y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (6 x y) + \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (6 x y) = 6 y

\frac{\partial}{\partial x} (y) = 0

= 2 x - 6 y + 0

Simplify

= 2 x - 6 y

(- 4, - 3), (4, 2)

\int_{0}^{2} 6 x - x^{2} d x

x \to \infty lim (\frac{a}{x})

\frac{d}{d x} (\frac{x}{x + \frac{a}{x}})

What is (\partial)/(\partial x)(x^2-6xy+y) ?
The answer to (\partial)/(\partial x)(x^2-6xy+y) is 2x-6y