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Popular >

y^'=3x+y,y(0)=3

Solution

y^{^{'}} = 3 x + y, y (0) = 3

Solution

y = - 3 (x + 1) + 6 e^{x}

Solution steps

y^{'} (x) = 3 x + y

Solve linear ODE:

y = - 3 (x + 1) + 6 e^{x}

y = - 3 (x + 1) + 6 e^{x}

Popular Examples

derivative of 3xsin(2x)

\frac{d}{d x} (3 x sin (2 x))

derivative of 1/(4-x^2)derivative of

\frac{1}{4 - x ^{2}}

integral of (2sin(t)cos(t))

\int (2 sin (t) cos (t)) d t

limit as x approaches 0+of (cos(x))/x

x \to 0 + lim (\frac{cos ( x )}{x})

limit as n approaches infinity of n!+n^3

n \to \infty lim (n! + n^{3})

Frequently Asked Questions (FAQ)

What is the solution for y^'=3x+y,y(0)=3 ?
The solution for y^'=3x+y,y(0)=3 is y=-3(x+1)+6e^x