What is (\partial)/(\partial s)(2s^2+t^2) ?

The answer to (\partial)/(\partial s)(2s^2+t^2) is 4s

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(\partial)/(\partial s)(2s^2+t^2)

\frac{\partial}{\partial s} (2 s^{2} + t^{2})

4 s

Solution steps

\frac{\partial}{\partial s} (2 s^{2} + t^{2})

Treat

t

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial s} (2 s^{2}) + \frac{\partial}{\partial s} (t^{2})

\frac{\partial}{\partial s} (2 s^{2}) = 4 s

\frac{\partial}{\partial s} (t^{2}) = 0

= 4 s + 0

Simplify

= 4 s

\frac{\partial}{\partial s} (e^{s^{3} + t^{2}})

\frac{1}{4} y^{^{''}} + y^{^{'}} + y = x^{2} - 5 x

\int e^{x} x + e^{x} d x

f (x) = \frac{3}{2 x ^{5}}

\int \frac{1}{t ^{2} - 6 t + 13} d t

What is (\partial)/(\partial s)(2s^2+t^2) ?
The answer to (\partial)/(\partial s)(2s^2+t^2) is 4s