What is the derivative of y=tan(4x^2) ?

The derivative of y=tan(4x^2) is sec^2(4x^2)*8x

What is the first derivative of y=tan(4x^2) ?

The first derivative of y=tan(4x^2) is sec^2(4x^2)*8x

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derivative of

y = tan (4 x^{2})

sec^{2} (4 x^{2}) \cdot 8 x

Solution steps

\frac{d}{d x} (tan (4 x^{2}))

Apply the chain rule:

sec^{2} (4 x^{2}) \frac{d}{d x} (4 x^{2})

= sec^{2} (4 x^{2}) \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (4 x^{2}) = 8 x

= sec^{2} (4 x^{2}) \cdot 8 x

x + y = 8

y^{^{''}} - 8 y^{^{'}} + 17 y = 0, y (0) = 4, y^{^{'}} (0) = - 1

\int \frac{t}{t ^{4} + 3} d t

x \to 1 - lim (arccos (- x^{3}))

What is the derivative of y=tan(4x^2) ?
The derivative of y=tan(4x^2) is sec^2(4x^2)*8x
What is the first derivative of y=tan(4x^2) ?
The first derivative of y=tan(4x^2) is sec^2(4x^2)*8x