What is the solution for (dy)/(dx)=1+y+x^2+yx^2 ?

The solution for (dy)/(dx)=1+y+x^2+yx^2 is y=e^{(x^3)/3+x+c_{1}}-1

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(dy)/(dx)=1+y+x^2+yx^2

\frac{d y}{d x} = 1 + y + x^{2} + y x^{2}

y = e^{\frac{x ^{3}}{3} + x + c_{1}} - 1

Solution steps

\frac{d y}{d x} = 1 + y + x^{2} + y x^{2}

Solve separable ODE:

y = e^{\frac{x ^{3}}{3} + x + c_{1}} - 1

y = e^{\frac{x ^{3}}{3} + x + c_{1}} - 1

ln (1 + e^{x + 1})

\frac{d}{d x} (\frac{1}{x ^{20}})

\frac{d}{d x} (- \frac{12}{x ^{3}})

\int \frac{1}{2} t cos (4) t^{2} d t

\frac{d}{d y} (y + 1)

What is the solution for (dy)/(dx)=1+y+x^2+yx^2 ?
The solution for (dy)/(dx)=1+y+x^2+yx^2 is y=e^{(x^3)/3+x+c_{1}}-1