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Popular >

y^'= y/(1+x)

Solution

y^{^{'}} = \frac{y}{1 + x}

Solution

y = e^{c_{1}} + e^{c_{1}} x

Solution steps

y^{'} (x) = \frac{y}{1 + x}

Solve separable ODE:

y = e^{c_{1}} + e^{c_{1}} x

y = e^{c_{1}} + e^{c_{1}} x

Popular Examples

integral of x^3-x^2-6x

\int x^{3} - x^{2} - 6 x d x

derivative of f(x)=ln(x^5)derivative of

f (x) = ln (x^{5})

derivative of sqrt(2+5x)

\frac{d}{d x} (2 + 5 x)

integral from 4 to 5 of xsqrt(x^2-16)

\int_{4}^{5} x x^{2} - 16 d x

(\partial)/(\partial x)(1/3 (x^2+2)^{3/2})

\frac{\partial}{\partial x} (\frac{1}{3} (x^{2} + 2)^{\frac{3}{2}})

Frequently Asked Questions (FAQ)

What is the solution for y^'= y/(1+x) ?
The solution for y^'= y/(1+x) is y=e^{c_{1}}+e^{c_{1}}x