en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'-2y=-3y^2

Solution

y^{^{'}} - 2 y = - 3 y^{2}

Solution

y = \frac{2}{- e ^{- 2 t - c_{1}} + 3}

Solution steps

y^{'} (t) - 2 y = - 3 y^{2}

Solve Bernoulli ODE:

y = \frac{2}{- e ^{- 2 t - c_{1}} + 3}

y = \frac{2}{- e ^{- 2 t - c_{1}} + 3}

Popular Examples

integral of arctan(t^2)

\int arctan (t^{2}) d t

tangent of y= 5/x tangent of

y = \frac{5}{x}

y^'+sin(x)y=-sin(x)

y^{^{'}} + sin (x) y = - sin (x)

integral of x*sin(x)

\int x \cdot sin (x) d x

tangent of f(x)=-0.5x^2,\at x=10 tangent of

f (x) = - 0.5 x^{2}, at x = 10

Frequently Asked Questions (FAQ)

What is the solution for y^'-2y=-3y^2 ?
The solution for y^'-2y=-3y^2 is y= 2/(-e^{-2t-c_{1)}+3}