What is the derivative of-x^2+4x+1 ?

The derivative of-x^2+4x+1 is -2x+4

What is the first derivative of-x^2+4x+1 ?

The first derivative of-x^2+4x+1 is -2x+4

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\frac{d}{d x} (- x^{2} + 4 x + 1)

- 2 x + 4

Solution steps

\frac{d}{d x} (- x^{2} + 4 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= - 2 x + 4 + 0

Simplify

= - 2 x + 4

\int \frac{( 4 x ^{2} + 4 )}{( x ^{2} - 2 x + 2 ) ^{2}} d x

\frac{d}{d x} ((3 + 2 x) e^{- 3 x})

9 y^{^{''}} - 12 y^{^{'}} + 4 y = 0

\frac{5 x ^{2}}{( 3 - 4 x ) ^{4}}

sin (3 t) cos (3 t)

What is the derivative of-x^2+4x+1 ?
The derivative of-x^2+4x+1 is -2x+4
What is the first derivative of-x^2+4x+1 ?
The first derivative of-x^2+4x+1 is -2x+4