What is the tangent of y=sin(4x)+sin^2(4x),(0,0) ?

The tangent of y=sin(4x)+sin^2(4x),(0,0) is y=4x

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tangent of y=sin(4x)+sin^2(4x),(0,0)

tangent of

y = sin (4 x) + sin^{2} (4 x), (0, 0)

y = 4 x

Solution steps

Find the slope of

y = sin (4 x) + sin^{2} (4 x) : \frac{d y}{d x} = cos (4 x) \cdot 4 + 4 sin (8 x)

Compute the slope of

y = sin (4 x) + sin^{2} (4 x)

(0, 0) : m = 4

Find the line with slope m=

4

and passing through

(0, 0) : y = 4 x

y = 4 x

3 y d x + 2 x d y = 0

\int_{0}^{\infty} e^{- 4 x} d x

f (x) = 2 x e^{2 x}

\int \frac{32 x ^{2}}{( x - 21 ) ( x + 7 ) ^{2}} d x

2 - \frac{3}{x}, at x = 1

What is the tangent of y=sin(4x)+sin^2(4x),(0,0) ?
The tangent of y=sin(4x)+sin^2(4x),(0,0) is y=4x