What is (\partial)/(\partial x)(ln(x+4y+2z)) ?

The answer to (\partial)/(\partial x)(ln(x+4y+2z)) is 1/(x+4y+2z)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(ln(x+4y+2z))

\frac{\partial}{\partial x} (ln (x + 4 y + 2 z))

\frac{1}{x + 4 y + 2 z}

Solution steps

\frac{\partial}{\partial x} (ln (x + 4 y + 2 z))

Treat

y, z

as constants

Apply the chain rule:

\frac{1}{x + 4 y + 2 z} \frac{\partial}{\partial x} (x + 4 y + 2 z)

= \frac{1}{x + 4 y + 2 z} \frac{\partial}{\partial x} (x + 4 y + 2 z)

\frac{\partial}{\partial x} (x + 4 y + 2 z) = 1

= \frac{1}{x + 4 y + 2 z} \cdot 1

Simplify

= \frac{1}{x + 4 y + 2 z}

\int_{- 2}^{3} (x^{2} - 3) d x

\frac{d}{d x} (sin (x + 2 y))

y^{^{'}} = 2 y

\frac{d}{d x} (\frac{1}{x ^{2} + 2})

\frac{7 e ^{x} + 5 e ^{- x}}{8}

What is (\partial)/(\partial x)(ln(x+4y+2z)) ?
The answer to (\partial)/(\partial x)(ln(x+4y+2z)) is 1/(x+4y+2z)