What is the derivative of 1/x-4x^2 ?

The derivative of 1/x-4x^2 is -1/(x^2)-8x

What is the first derivative of 1/x-4x^2 ?

The first derivative of 1/x-4x^2 is -1/(x^2)-8x

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Popular >

\frac{d}{d x} (\frac{1}{x} - 4 x^{2})

- \frac{1}{x ^{2}} - 8 x

Solution steps

\frac{d}{d x} (\frac{1}{x} - 4 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{x}) - \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{d}{d x} (4 x^{2}) = 8 x

= - \frac{1}{x ^{2}} - 8 x

2 x^{2} + 3, (- 2, 1)

\frac{d}{d x} (\frac{x ^{3}}{x})

x \to 0 + lim (sin (3 x) ln (x))

\int \frac{1}{2} u d u

\int_{- 7}^{- 3} \frac{1}{x} d x

What is the derivative of 1/x-4x^2 ?
The derivative of 1/x-4x^2 is -1/(x^2)-8x
What is the first derivative of 1/x-4x^2 ?
The first derivative of 1/x-4x^2 is -1/(x^2)-8x