What is the tangent of f(x)=3x^{-2},\at x=4 ?

The tangent of f(x)=3x^{-2},\at x=4 is y=-3/32 x+9/16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=3x^{-2},\at x=4

tangent of

f (x) = 3 x^{- 2}, at x = 4

y = - \frac{3}{32} x + \frac{9}{16}

Solution steps

Find the tangent point:

(4, \frac{3}{16})

Find the slope of

f (x) = 3 x^{- 2} : \frac{df ( x )}{d x} = - \frac{6}{x ^{3}}

Compute the slope of

f (x) = 3 x^{- 2}

x = 4 : m = - \frac{3}{32}

Find the line with slope m=

- \frac{3}{32}

and passing through

(4, \frac{3}{16}) : y = - \frac{3}{32} x + \frac{9}{16}

y = - \frac{3}{32} x + \frac{9}{16}

x \to + 0 lim (1 + sinh (2 x))

\frac{d y}{d x} = \frac{6 x}{5 y}

\int_{0}^{π^{2}} sin (x) d x

x \to \infty lim (3 x + 1)

\int \frac{x}{x + 1} d x

What is the tangent of f(x)=3x^{-2},\at x=4 ?
The tangent of f(x)=3x^{-2},\at x=4 is y=-3/32 x+9/16