What is area x=-2,x=1,y=6x,y=x^2-7 ?

The answer to area x=-2,x=1,y=6x,y=x^2-7 is 53/3

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area x=-2,x=1,y=6x,y=x^2-7

area

x = - 2, x = 1, y = 6 x, y = x^{2} - 7

\frac{53}{3}

Decimal Notation

17.66666 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{1} 6 x - (x^{2} - 7) d x

Solve

\int_{- 2}^{1} 6 x - (x^{2} - 7) d x : \frac{53}{3}

The area is:

= \frac{53}{3}

n = 1 \sum \infty n^{5} (1 + n^{6})^{2}

\int e^{- x^{2} - 2 x + 7} (x + 1) d x

y^{^{''}} + 16 y = 3 sin (4 t), y (0) = 0, y^{^{'}} (0) = 0

y = x^{3} - 9 x, (- 3, 0)

\int_{0}^{1} 7 e^{x^{2}} d x

What is area x=-2,x=1,y=6x,y=x^2-7 ?
The answer to area x=-2,x=1,y=6x,y=x^2-7 is 53/3