What is the solution for (x+2)y^'-y= 3/(x+2) ?

The solution for (x+2)y^'-y= 3/(x+2) is y=-3/(2(x+2))+c_{1}(x+2)

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(x+2)y^'-y= 3/(x+2)

(x + 2) y^{^{'}} - y = \frac{3}{x + 2}

y = - \frac{3}{2 ( x + 2 )} + c_{1} (x + 2)

Solution steps

(x + 2) y^{'} (x) - y = \frac{3}{x + 2}

Solve linear ODE:

y = - \frac{3}{2 ( x + 2 )} + c_{1} (x + 2)

y = - \frac{3}{2 ( x + 2 )} + c_{1} (x + 2)

x \to \infty + lim (\frac{1}{x})

(\frac{t}{y}) d y + (1 + ln (y)) d t = 0

\int \frac{1}{6} sec (x) tan (x) d x

\int 5 tan (3 x) ln (sec (3 x)) d x

\frac{d}{d x} ((a - \frac{b}{x})^{2})

What is the solution for (x+2)y^'-y= 3/(x+2) ?
The solution for (x+2)y^'-y= 3/(x+2) is y=-3/(2(x+2))+c_{1}(x+2)