What is the tangent of y=16sqrt(x),(4,32) ?

The tangent of y=16sqrt(x),(4,32) is y=4x+16

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tangent of y=16sqrt(x),(4,32)

tangent of

y = 16 x, (4, 32)

y = 4 x + 16

Solution steps

Find the slope of

y = 16 x : \frac{d y}{d x} = \frac{8}{x}

Compute the slope of

y = 16 x

(4, 32) : m = 4

Find the line with slope m=

4

and passing through

(4, 32) : y = 4 x + 16

y = 4 x + 16

\int \frac{( x - 3 ) ^{3}}{x ^{2} - 9} d x

\int \frac{x sin ( x )}{cos ^{2} ( x )} d x

\frac{\partial}{\partial x} (x yz ln (x + y))

x \to 4 - lim (8 - 2 x)

x \to - 8 - lim (\frac{- 2 x}{x + 8})

What is the tangent of y=16sqrt(x),(4,32) ?
The tangent of y=16sqrt(x),(4,32) is y=4x+16