What is the integral of 6tan(x)sec^3(x) ?

The integral of 6tan(x)sec^3(x) is 2sec^3(x)+C

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integral of 6tan(x)sec^3(x)

\int 6 tan (x) sec^{3} (x) d x

2 sec^{3} (x) + C

Solution steps

\int 6 tan (x) sec^{3} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int tan (x) sec^{3} (x) d x

Apply u-substitution

: \int \frac{1}{3} d u

= 6 \cdot \int \frac{1}{3} d u

Integral of a constant:

\int a d x = a x

= 6 \cdot \frac{1}{3} u

Substitute back

u = sec^{3} (x)

= 6 \cdot \frac{1}{3} sec^{3} (x)

Simplify

6 \cdot \frac{1}{3} sec^{3} (x) : 2 sec^{3} (x)

= 2 sec^{3} (x)

Add a constant to the solution

= 2 sec^{3} (x) + C

f (x) = 8 cos (x)

\int e^{- x^{8}} d x

y = x^{2} - 2 x, y = x

x y^{'} + 2 y = x + 2

What is the integral of 6tan(x)sec^3(x) ?
The integral of 6tan(x)sec^3(x) is 2sec^3(x)+C