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Popular >

integral of-y/(z^2)

Solution

\int - \frac{y}{z ^{2}} d z

Solution

\frac{y}{z} + C

Solution steps

\int - \frac{y}{z ^{2}} d z

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - y \cdot \int \frac{1}{z ^{2}} d z

Apply the Power Rule

: - \frac{1}{z}

= - y (- \frac{1}{z})

Simplify

- y (- \frac{1}{z}) : \frac{y}{z}

= \frac{y}{z}

Add a constant to the solution

= \frac{y}{z} + C

Popular Examples

integral of 1/(sqrt(-x^2-18x))

\int \frac{1}{- x ^{2} - 18 x} d x

integral of (10)/((t^2+1)^{3/2)}

\int \frac{10}{( t ^{2} + 1 ) ^{\frac{3}{2}}} d t

integral of 1/((x-5)^2)

\int \frac{1}{( x - 5 ) ^{2}} d x

limit as x approaches 3 of (x-5)/(|x-5|)

x \to 3 lim (\frac{x - 5}{∣ x - 5 ∣})

(sinh (x))^{^{'}}

Frequently Asked Questions (FAQ)

What is the integral of-y/(z^2) ?
The integral of-y/(z^2) is y/z+C