What is the tangent of y=6x^2+3x-9 ?

The tangent of y=6x^2+3x-9 is y=(12a_{0}+3)x-6a_{0}^2-9

Popular >

tangent of y=6x^2+3x-9

tangent of

y = 6 x^{2} + 3 x - 9

y = (12 a_{0} + 3) x - 6 a_{0}^{2} - 9

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 6 a_{0}^{2} + 3 a_{0} - 9)

Find the slope of

y = 6 x^{2} + 3 x - 9 : \frac{d y}{d x} = 12 x + 3

Compute the slope of

y = 6 x^{2} + 3 x - 9

x = a_{0} : m = 12 a_{0} + 3

Find the line with slope m=

12 a_{0} + 3

and passing through

(a_{0}, 6 a_{0}^{2} + 3 a_{0} - 9) : y = (12 a_{0} + 3) x - 6 a_{0}^{2} - 9

y = (12 a_{0} + 3) x - 6 a_{0}^{2} - 9

\int e^{- 2 u} d u

\int_{1}^{3} (3 x + 2)^{2} d x

\int_{0}^{x^{2}} x sin (t^{2}) d t

\frac{\partial}{\partial x} (\frac{x}{3 + 6 x ^{2} + 7 y ^{2}})

\frac{d}{d x} (\frac{1}{x - 1} + \frac{1}{4 - x})

What is the tangent of y=6x^2+3x-9 ?
The tangent of y=6x^2+3x-9 is y=(12a_{0}+3)x-6a_{0}^2-9