What is the tangent of f(x)=(e^x)/x ,\at x=1 ?

The tangent of f(x)=(e^x)/x ,\at x=1 is y=e

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tangent of f(x)=(e^x)/x ,\at x=1

tangent of

f (x) = \frac{e ^{x}}{x}, at x = 1

y = e

Solution steps

Find the tangent point:

(1, e)

Find the slope of

f (x) = \frac{e ^{x}}{x} : \frac{df ( x )}{d x} = \frac{e ^{x} x - e ^{x}}{x ^{2}}

Compute the slope of

f (x) = \frac{e ^{x}}{x}

x = 1 : m = 0

Find the line with slope m=

0

and passing through

(1, e) : y = e

y = e

\frac{\partial}{\partial x} (x^{2} y + y^{2} z + x z^{2})

\frac{d}{d x} (\frac{3 x + 2}{5 - 4 x})

\int x^{7} d x

\int \frac{2}{12 - 5 x} d x

arccos (x)

What is the tangent of f(x)=(e^x)/x ,\at x=1 ?
The tangent of f(x)=(e^x)/x ,\at x=1 is y=e