What is the derivative of ln(y^2) ?

The derivative of ln(y^2) is 2/y

What is the first derivative of ln(y^2) ?

The first derivative of ln(y^2) is 2/y

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derivative of

ln (y^{2})

\frac{2}{y}

Solution steps

\frac{d}{d y} (ln (y^{2}))

Apply the chain rule:

\frac{1}{y ^{2}} \frac{d}{d y} (y^{2})

= \frac{1}{y ^{2}} \frac{d}{d y} (y^{2})

\frac{d}{d y} (y^{2}) = 2 y

= \frac{1}{y ^{2}} \cdot 2 y

Simplify

\frac{1}{y ^{2}} \cdot 2 y : \frac{2}{y}

= \frac{2}{y}

\frac{d}{d x} (arctan (1 - x))

\int_{2}^{3} 2 x d x

\frac{7}{4} x^{4} - \frac{6}{5} x^{3}

x \to 0 lim (\frac{e ^{x} - 1}{17 x})

f (x) = 3^{x} - 5 e^{x}

What is the derivative of ln(y^2) ?
The derivative of ln(y^2) is 2/y
What is the first derivative of ln(y^2) ?
The first derivative of ln(y^2) is 2/y