What is the derivative of 2x^3-3x+1 ?

The derivative of 2x^3-3x+1 is 6x^2-3

What is the first derivative of 2x^3-3x+1 ?

The first derivative of 2x^3-3x+1 is 6x^2-3

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\frac{d}{d x} (2 x^{3} - 3 x + 1)

6 x^{2} - 3

Solution steps

\frac{d}{d x} (2 x^{3} - 3 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= 6 x^{2} - 3 + 0

Simplify

= 6 x^{2} - 3

7 cos (2 t)

\int ddd

\int (x + 3) (x - 2) d x

\frac{d}{d x} (\frac{1}{x ^{4}})

\frac{1}{4 s ^{2} + 1}

What is the derivative of 2x^3-3x+1 ?
The derivative of 2x^3-3x+1 is 6x^2-3
What is the first derivative of 2x^3-3x+1 ?
The first derivative of 2x^3-3x+1 is 6x^2-3