What is (\partial)/(\partial x)(2x^2y) ?

The answer to (\partial)/(\partial x)(2x^2y) is 4xy

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(\partial)/(\partial x)(2x^2y)

\frac{\partial}{\partial x} (2 x^{2} y)

4 x y

Solution steps

\frac{\partial}{\partial x} (2 x^{2} y)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 y \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 y \cdot 2 x^{2 - 1}

Simplify

= 4 x y

y^{^{''}} + 16 y = 4 sec (4 t)

\frac{d}{d x} (ln (2 x^{4} - x^{3} + 3 x^{2} - 3 x))

f (x) = ln (1)

\int x e^{(3 x)} d x

\int \frac{15}{4 + 5 x} d x

What is (\partial)/(\partial x)(2x^2y) ?
The answer to (\partial)/(\partial x)(2x^2y) is 4xy