What is the solution for 2t(dy)/(dt)-4y=sqrt(t) ?

The solution for 2t(dy)/(dt)-4y=sqrt(t) is y=-(t^{1/2})/3+c_{1}t^2

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2t(dy)/(dt)-4y=sqrt(t)

2 t \frac{d y}{d t} - 4 y = t

y = - \frac{t ^{\frac{1}{2}}}{3} + c_{1} t^{2}

Solution steps

2 t \frac{d y}{d t} - 4 y = t

Solve linear ODE:

y = - \frac{t ^{\frac{1}{2}}}{3} + c_{1} t^{2}

y = - \frac{t ^{\frac{1}{2}}}{3} + c_{1} t^{2}

n = 1 \sum \infty \frac{1}{4 ^{n}}

(t^{2} - 3 t + 2) sin (3 t)

y = sin (9 x) + cos (2 x)

\frac{d}{d x} (3 arcsin (\frac{x}{2}))

\int 2 sin (3 x) d x

What is the solution for 2t(dy)/(dt)-4y=sqrt(t) ?
The solution for 2t(dy)/(dt)-4y=sqrt(t) is y=-(t^{1/2})/3+c_{1}t^2