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Popular >

integral of 1/(2x^4)

Solution

\int \frac{1}{2 x ^{4}} d x

Solution

- \frac{1}{6 x ^{3}} + C

Solution steps

\int \frac{1}{2 x ^{4}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{x ^{4}} d x

Apply the Power Rule

: - \frac{1}{3 x ^{3}}

= \frac{1}{2} (- \frac{1}{3 x ^{3}})

Simplify

\frac{1}{2} (- \frac{1}{3 x ^{3}}) : - \frac{1}{6 x ^{3}}

= - \frac{1}{6 x ^{3}}

Add a constant to the solution

= - \frac{1}{6 x ^{3}} + C

Popular Examples

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\int (8 x + 5) 4 x^{2} + 5 x d x

taylor-1/(x^2),2 taylor

- \frac{1}{x ^{2}}, 2

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y^{^{'}} = 0

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\int \frac{x}{6} + π d x

Frequently Asked Questions (FAQ)

What is the integral of 1/(2x^4) ?
The integral of 1/(2x^4) is -1/(6x^3)+C