What is (\partial)/(\partial z)(xsin(y)+ze^x) ?

The answer to (\partial)/(\partial z)(xsin(y)+ze^x) is e^x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial z)(xsin(y)+ze^x)

\frac{\partial}{\partial z} (x sin (y) + z e^{x})

e^{x}

Solution steps

\frac{\partial}{\partial z} (x sin (y) + z e^{x})

Treat

x, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (x sin (y)) + \frac{\partial}{\partial z} (z e^{x})

\frac{\partial}{\partial z} (x sin (y)) = 0

\frac{\partial}{\partial z} (z e^{x}) = e^{x}

= 0 + e^{x}

Simplify

= e^{x}

\int 2 e^{- 0.1 x} d x

\frac{1}{( s ^{2} + 2 s + 2 ) ( s + 1 )}

\int 5 sin (6 π t) d t

\int - \frac{1}{2 x + 1} d x

\frac{d}{d x} (\frac{2}{2 x - 1} - \frac{1}{x})

What is (\partial)/(\partial z)(xsin(y)+ze^x) ?
The answer to (\partial)/(\partial z)(xsin(y)+ze^x) is e^x