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Popular >

y^'=8xy-2x,y(0)=16

Solution

y^{^{'}} = 8 x y - 2 x, y (0) = 16

Solution

y = \frac{63 e ^{4 x^{2}}}{4} + \frac{1}{4}

Solution steps

y^{'} (x) = 8 x y - 2 x

Solve separable ODE:

y = \frac{63 e ^{4 x^{2}}}{4} + \frac{1}{4}

y = \frac{63 e ^{4 x^{2}}}{4} + \frac{1}{4}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=8xy-2x,y(0)=16 ?
The solution for y^'=8xy-2x,y(0)=16 is y=(63e^{4x^2})/4+1/4