What is the solution for y^{''}-y=0,y(0)=2,y^'(0)=-2 ?

The solution for y^{''}-y=0,y(0)=2,y^'(0)=-2 is y=2e^{-t}

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y^{''}-y=0,y(0)=2,y^'(0)=-2

y^{^{''}} - y = 0, y (0) = 2, y^{^{'}} (0) = - 2

y = 2 e^{- t}

Solution steps

y^{''} (t) - y = 0

Solve linear ODE:

y = 2 e^{- t}

y = 2 e^{- t}

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What is the solution for y^{''}-y=0,y(0)=2,y^'(0)=-2 ?
The solution for y^{''}-y=0,y(0)=2,y^'(0)=-2 is y=2e^{-t}