What is the integral of 3/y ?

The integral of 3/y is 3ln|y|+C

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integral of 3/y

\int \frac{3}{y} d y

3 ln ∣ y ∣ + C

Solution steps

\int \frac{3}{y} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{1}{y} d y

Use the common integral:

\int \frac{1}{y} d y = ln (∣ y ∣)

= 3 ln ∣ y ∣

Add a constant to the solution

= 3 ln ∣ y ∣ + C

\int_{1}^{3} \frac{2 x ^{2} + 3 x - 2}{x} d x

\frac{\partial}{\partial s} (\frac{s}{t})

\int \frac{x}{3 x ^{2} - 4} d x

\int - 19 x^{2} - 2 x + 8 d x

\frac{\partial}{\partial x} (1 + x^{3} + y^{3})