What is the integral from 1 to 7 of x^{-3} ?

The integral from 1 to 7 of x^{-3} is 24/49

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integral from 1 to 7 of x^{-3}

\int_{1}^{7} x^{- 3} d x

\frac{24}{49}

Decimal Notation

0.48979 \dots

Solution steps

\int_{1}^{7} x^{- 3} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{7}

= [- \frac{1}{2 x ^{2}}]_{1}^{7}

Compute the boundaries:

\frac{24}{49}

= \frac{24}{49}

\int \frac{6}{1 + 6 x} d x

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\int 1 - \frac{2}{x} d x

x \to \infty lim (- x^{2})

What is the integral from 1 to 7 of x^{-3} ?
The integral from 1 to 7 of x^{-3} is 24/49