What is the derivative of f(x)=9sqrt(x)sin(x) ?

The derivative of f(x)=9sqrt(x)sin(x) is 9((sin(x))/(2sqrt(x))+sqrt(x)cos(x))

What is the first derivative of f(x)=9sqrt(x)sin(x) ?

The first derivative of f(x)=9sqrt(x)sin(x) is 9((sin(x))/(2sqrt(x))+sqrt(x)cos(x))

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derivative of

f (x) = 9 x sin (x)

9 (\frac{sin ( x )}{2 x} + x cos (x))

Solution steps

\frac{d}{d x} (9 x sin (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (x sin (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = sin (x)

= 9 (\frac{d}{d x} (x) sin (x) + \frac{d}{d x} (sin (x)) x)

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (sin (x)) = cos (x)

= 9 (\frac{1}{2 x} sin (x) + cos (x) x)

\frac{1}{2 x} sin (x) = \frac{sin ( x )}{2 x}

= 9 (\frac{sin ( x )}{2 x} + x cos (x))

f (x) = e^{- 5 x}, at x = 0

\frac{d}{d s} (\frac{s ^{2} - 8 s + 15}{s ^{2} + 3 s + 2})

2 y y^{^{'}} + 4 = y^{2} + 4 x

x (7 x + 3)^{\frac{1}{3}}

\int_{0}^{1} x^{3} (1 + x^{4})^{3} d x

What is the derivative of f(x)=9sqrt(x)sin(x) ?
The derivative of f(x)=9sqrt(x)sin(x) is 9((sin(x))/(2sqrt(x))+sqrt(x)cos(x))
What is the first derivative of f(x)=9sqrt(x)sin(x) ?
The first derivative of f(x)=9sqrt(x)sin(x) is 9((sin(x))/(2sqrt(x))+sqrt(x)cos(x))