What is the integral of 10m^{-2.3}+5m^{3.6} ?

The integral of 10m^{-2.3}+5m^{3.6} is -(7.69230…)/(m^{1.3)}+1.08695…m^{4.6}+C

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integral of 10m^{-2.3}+5m^{3.6}

\int 10 m^{- 2.3} + 5 m^{3.6} d m

- \frac{7.69230 \dots}{m ^{1.3}} + 1.08695 \dots m^{4.6} + C

Solution steps

\int 10 m^{- 2.3} + 5 m^{3.6} d m

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 10 m^{- 2.3} d m + \int 5 m^{3.6} d m

\int 10 m^{- 2.3} d m = - \frac{7.69230 \dots}{m ^{1.3}}

\int 5 m^{3.6} d m = 1.08695 \dots m^{4.6}

= - \frac{7.69230 \dots}{m ^{1.3}} + 1.08695 \dots m^{4.6}

Add a constant to the solution

= - \frac{7.69230 \dots}{m ^{1.3}} + 1.08695 \dots m^{4.6} + C

\int \frac{1}{u ^{2} - 1} d u

x \cdot 5 x^{2}

\int \frac{1}{1 + cos ^{2} ( θ )} d θ

\frac{d}{d x} (arccos (sin (x^{2} + 9 x)))

f (x) = 3 x + 4

What is the integral of 10m^{-2.3}+5m^{3.6} ?
The integral of 10m^{-2.3}+5m^{3.6} is -(7.69230…)/(m^{1.3)}+1.08695…m^{4.6}+C