What is the tangent of f(x)= 2/(4-x),\at x=1 ?

The tangent of f(x)= 2/(4-x),\at x=1 is y= 2/9 x+4/9

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tangent of f(x)= 2/(4-x),\at x=1

tangent of

f (x) = \frac{2}{4 - x}, at x = 1

y = \frac{2}{9} x + \frac{4}{9}

Solution steps

Find the tangent point:

(1, \frac{2}{3})

Find the slope of

f (x) = \frac{2}{4 - x} : \frac{df ( x )}{d x} = \frac{2}{( 4 - x ) ^{2}}

Compute the slope of

f (x) = \frac{2}{4 - x}

x = 1 : m = \frac{2}{9}

Find the line with slope m=

\frac{2}{9}

and passing through

(1, \frac{2}{3}) : y = \frac{2}{9} x + \frac{4}{9}

y = \frac{2}{9} x + \frac{4}{9}

\int_{0}^{1} cos (\frac{π t}{2}) d t

x \to \infty lim (e^{- s (x)})

\int 2 x + 1 - x e^{x^{2}} d x

\frac{d}{d x} ((x - 2)^{- 1})

\frac{d ^{2}}{d x ^{2}} (7 e^{- x^{2}})

What is the tangent of f(x)= 2/(4-x),\at x=1 ?
The tangent of f(x)= 2/(4-x),\at x=1 is y= 2/9 x+4/9