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Popular >

area y=-x^2+1,(0,1)

Solution

area

y = - x^{2} + 1, (0, 1)

Solution

\frac{2}{3}

+1

Decimal Notation

0.66666 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} - x^{2} + 1 d x

Solve

\int_{0}^{1} - x^{2} + 1 d x : \frac{2}{3}

The area is:

= \frac{2}{3}

Popular Examples

derivative of (7x+1)/(2sqrt(x)-3)derivative of

\frac{7 x + 1}{2 x - 3}

integral from 0 to 1 of x^3ln(x^8)

\int_{0}^{1} x^{3} ln (x^{8}) d x

tangent of f(x)=(sqrt(x))/(x+3),\at x=1 tangent of

f (x) = \frac{x}{x + 3}, at x = 1

derivative of cos^2(4pix)

\frac{d}{d x} (cos^{2} (4 π x))

tangent of f(x)=x^2+2 tangent of

f (x) = x^{2} + 2

Frequently Asked Questions (FAQ)

What is area y=-x^2+1,(0,1) ?
The answer to area y=-x^2+1,(0,1) is 2/3