What is the first derivative of 3x^2-5 ?

The first derivative of 3x^2-5 is 6x

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derivative of 3x^2-5

\frac{d}{d x} (3 x^{2} - 5)

6 x

Solution steps

\frac{d}{d x} (3 x^{2} - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (5)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (5) = 0

= 6 x - 0

Simplify

= 6 x

y^{^{'}} = \frac{5 y}{x}

f (x) = 2 x^{2} + x, at x = 0

(1 + x^{2}) (e^{2 t} d t - e^{x} d x) - (1 + x) = 0

x \to π lim (\frac{x}{4} - \frac{π}{2})

x \to 2 lim (\frac{( x - 3 )}{x - 2})