What is the limit as x approaches 2 of 1/((2-x)^2) ?

The limit as x approaches 2 of 1/((2-x)^2) is infinity

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limit as x approaches 2 of 1/((2-x)^2)

x \to 2 lim (\frac{1}{( 2 - x ) ^{2}})

\infty

Solution steps

x \to 2 lim (\frac{1}{( 2 - x ) ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 2 - lim (\frac{1}{( 2 - x ) ^{2}}) = \infty

x \to 2 + lim (\frac{1}{( 2 - x ) ^{2}}) = \infty

= \infty

\int \frac{s ^{2}}{s ^{3} + 5} d s

\frac{d}{d x} (\frac{x}{x - 1} - \frac{1}{ln ( x )})

y = x^{2} + 3, (- 5, 28)

f (x) = x^{2} + x

\int x^{2} a^{2} + a^{2} x^{2} d x

What is the limit as x approaches 2 of 1/((2-x)^2) ?
The limit as x approaches 2 of 1/((2-x)^2) is infinity