What is the tangent of f(x)=2x^4-6x^2,\at x=1 ?

The tangent of f(x)=2x^4-6x^2,\at x=1 is y=-4x

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tangent of f(x)=2x^4-6x^2,\at x=1

tangent of

f (x) = 2 x^{4} - 6 x^{2}, at x = 1

y = - 4 x

Solution steps

Find the tangent point:

(1, - 4)

Find the slope of

f (x) = 2 x^{4} - 6 x^{2} : \frac{df ( x )}{d x} = 8 x^{3} - 12 x

Compute the slope of

f (x) = 2 x^{4} - 6 x^{2}

x = 1 : m = - 4

Find the line with slope m=

- 4

and passing through

(1, - 4) : y = - 4 x

y = - 4 x

x y 2 = 2 + x y

\int_{0}^{1} 2 x^{2} d x

\int \frac{1}{x ^{2} - 2 x - 8} d x

f (x) = x^{2} - 20 x, g (x) = 0

\frac{d}{d x} (ln (\frac{1}{6 x}))

What is the tangent of f(x)=2x^4-6x^2,\at x=1 ?
The tangent of f(x)=2x^4-6x^2,\at x=1 is y=-4x